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Re: point particles



If mg=qE the net force is zero, the CM remains at rest, and so you ARE
riding it ;>)

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
http://www.velocity.net/~trebor/
trebor@velocity.net
----- Original Message -----
From: "John Mallinckrodt" <ajm@CSUPOMONA.EDU>
To: <PHYS-L@lists.nau.edu>
Sent: Thursday, January 22, 2004 4:24 PM
Subject: Re: point particles


Isn't it so that (I think it's Chasle's theorem):
The instantaneous general motion of any rigid body can be viewed as the
compounding of
1) a pure translational motion of the body, and
2) a rotation about any freely choosable point fixed in the (extended)
body.

It follows that if one rides on a fixed body point and observes the body,
only a pure rotation will be directly observed at any instant.
I think this is quite intuitive.

I would agree that what you have said here is not only quite
intuitive, but, in fact, almost a tautology. In the case under
consideration, however, no "riding" is actually required. I simply
ask you to consider the motion of a rod with a UNIFORM mass
distribution and positive electric charge at ONE end subject to
oppositely directed and uniform gravitational and electric fields
with mg = qE.

John Mallinckrodt
Cal Poly Pomona