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Re: Fluids Physlet



It seems to me then that I see a rare note of unanimity here.
Apart from the very, very small depression with pressure
effect on a wood block if porous, the dominant effect
is to lower the block, when the oil level falls below the
block's top.

Brian W

At 09:25 PM 8/18/2003 -0400, you wrote:
Addendum:

In 2) below, c is the total height of the wood block.
Sorry.

Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor
----- Original Message -----
From: "Bob Sciamanda" <trebor@VELOCITY.NET>
To: <PHYS-L@lists.nau.edu>
Sent: Monday, August 18, 2003 9:13 PM
Subject: Re: Fluids Physlet


| I agree with everything you say, Stuart. I don't think any (A,B or C) is
| physical.
|
| 1.) When the top of the wood is covered in oil then the fraction of wood
| floating is:
| r = (wood - water)/(oil - water), as in my previous post. This is
independent
| of the oil depth - disqualifying B and C.
|
| 2) But when the wood top is not covered with oil:
| r = (water - wood + oil*x/c) /(water), where x is the oil depth.
|
| 3) When x=0, this is r = (water - wood)/ water - the usual Archimedes
problem.
| This is clearly smaller than the original r. in (1)
| So you are right - the block doesn't move until the oil level goes
beneath the
| wood block's top - then it sinks lower. This disqualifies A.
|
| Bob Sciamanda (W3NLV)
| Physics, Edinboro Univ of PA (em)
| trebor@velocity.net
| http://www.velocity.net/~trebor
| | ----- Original Message -----
| | =46rom: "Stuart Leinoff" <Leinoffs@ACC.SUNYACC.EDU>
| | To: <PHYS-L@lists.nau.edu>
| | Sent: Monday, August 18, 2003 3:35 PM
| | Subject: Fluids Physlet
| |
| |
| | > Greetings,
| | >
| | > Ok, I am stumped by the Physlet on fluids found at (among other pla=
| | ce=3D
| | > s):
| | >
| | > http://webphysics.davidson.edu/physletprob/ch8_problems/ch8_11_flui=
| | ds=3D
| | > /fluids_2.html=3D20
| | >
| | > The alleged answer is that "B" is the only "physical" animation, bu=
| | t =3D
| | > I do not see why the block of wood will float higher in this animat=
| | io=3D
| | > n as oil is drawn away but before the block of wood breaks the surf=
| | ac=3D
| | > e of the oil.
| | >
| | > By Archimedes Principle and the equilibrium principle, the weight o=
| | f =3D
| | > the block (constant) should equal the weight of the fluids displace=
| | d;=3D
| | > which would be the sum of the (oil displaced)'s weight and the (wa=
| | te=3D
| | > r displaced)'s weight. Why would the ratio of these two weights ch=
| | an=3D
| | > ge when the block is less deep under the oil?
| | >
| | > If we calculate the buoyancy force based on the difference between =
| | th=3D
| | > e water's pressure pushing up on the bottom surface of the block an=
| | d =3D
| | > the oil's pressure pushing down on the top surface, again I do not =
| | se=3D
| | > e why this "difference" would be different before the oil no longer=
| | c=3D
| | > overs the top surface of the block.
| | >
| | > Animation "A" does not seem physical to me because once the block i=
| | s =3D
| | > no longer under the oil, it should sink deeper into the water.
| | >
| | > I would appreciate someone else's insight into this.
| | >
| | > Thanks,
| | >
| | >
| | > Stuart Leinoff
| | > Professor of Physics
| | > Science Division Chair
| | > ACC


Brian Whatcott Altus OK Eureka!