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Re: TdS is not dQ or d(anything)



Well, actually not quite. Without needlessly complicating the
discussion, 0-forms bear the added responsibility of being "smooth", a
condition not usually imposed on all scalars.

On Wed, 14 May 2003, John S. Denker wrote:

I wrote:
>> Scalars and 0-forms are essentially synonymous.



On 05/13/2003 08:36 PM, Bob Sciamanda wrote:

The qualification "essentially" is troubling - what does it mean?

Operationally, when you are doing calculations,
0-forms and scalars are interchangeable.

The distinction is epistemological: 0-forms
are defined in terms of scalars, not the other
way around.

(This is splitting hairs, but if I hadn't put
that qualification in there, I 'spect somebody
would have called me on it.)


--
"What did Barrow's lectures contain? Bourbaki writes with some
scorn that in his book in a hundred pages of the text there are about 180
drawings. (Concerning Bourbaki's books it can be said that in a thousand
pages there is not one drawing, and it is not at all clear which is
worse.)"
V. I. Arnol'd in
Huygens & Barrow, Newton & Hooke