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Re: gradients and exterior derivatives



My rather rusty understanding matches with everything John Denker wrote
below.

Regarding the "fishscale" visualizations:

If I understand you diagrams correctly, they are more about how to
pictorially represent (visualize) one-forms, rather than how to pictorially
represent non-conservative fields.

The biggest advantage I see to the "fishscale" diagrams is the introduction
of the notion of "up/down" OR "+ or -" with respect to the directionality.
The "standard" method (ones I've seen in books) of representing one-forms is
with a family of surfaces and that method loses the "up/down" sense of
directionality.

The family of surfaces method does get the notion of magnitude (The closer
the surfaces are to each other the larger the magnitude. It also, when
combined with arrow pictures of a vector-field allows one to visualize the
inner-product of a vector with the dual of some one-form.

i.e. <V,F> where V is a vector field and where F is the dual to some
one-form field. The magnitude of the inner product is proportional to the
number of "piercings" of arrows through surfaces.

One other slight disadvantage is that the fish scale picture is inherently
2-dimensional, I think. A family of surfaces can sometimes give you a
3-dimensional perspective impression of the one-form.

This visualization is very tricky as you point out and nothing is entirely
satisfactory it seems. This may boil down to the need to have several ways
to visualize of which the "fishscales" adds an important element.

Comments?

Joel Rauber


On 04/28/2003 02:22 PM, RAUBER, JOEL wrote:

MTW (Misner, Thorne and Wheeler) give some discussion to
the above. They
state that most properly one should view the gradient of
the potential as a
one-form. I.e. the gradient of a function is a one-form,
i.e. the exterior
derivative of the function.

Thanks for pointing this out.
I am happy to adopt the MTW terminology.

I think we all agree about the physics.
Let me see if I can re-state the physics
in the MTW terminology:

1) The gradient of a scalar potential is most properly
considered a one-form.

2) The exterior derivative of a scalar potential
is a one-form. It is 100% identical to the gradient,
because
del /\ A = del A
automatically for any scalar A. Indeed
X /\ A = X A
for any X whatsoever, provided A is a scalar.

3) For a non-scalar B, the generic derivative
del B is not the same as the exterior derivative
del /\ B, but we don't need to worry about that
right now.

4a) The gradient VECTOR that we learned in infancy
is the dual of the gradient ONE-FORM mentioned in
item 1.

4b) You can't form the dual without a metric.

4c) If you have a nice Cartesian metric, forming
the dual is trivial: the components of the vector
are numerically equal to the components of the
one-form.

5) The things you really need, such as Taylor
expansions, work just fine without a metric.
Just write the derivative as a one-form and
turn the crank.

=======================================

On a related topic, I revised and extended the
writeup on visualizing non-conservative fields.
http://www.monmouth.com/~jsd/physics/non-conservative.htm

Among other things, I added a new figure

http://www.monmouth.com/~jsd/physics/non-conservative.htm#fig-betatron

which
a) Properly portrays the electric field inside a
betatron.
b) Has constant curl everywhere. (Verify this
yourself. It's fun.)
c) Demonstrates the power of the fish-scale technique
to represent one-forms where the magnitude and direction
are both changing from point to point. (Previous
examples had uniform magnitude.)