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Re: There's work, and then there's work



Chuck Britton wrote:

At 10:28 AM -0800 2/3/03, David Rutherford wrote:

I don't know much about superconductivity, but shouldn't you be able
charge the capacitor in the absence of resistance (superconducting
circuit). Then, since the energy loss doesn't depend on R, you would
still have to get 1/2 CV^2 for the energy stored on the capacitor. But
where does the other 1/2 CV^2 energy go, in this case? Or maybe the
energy stored on the capacitor in the first place is actually CV^2, not
1/2 CV^2, even in the presence of nonzero R.

Superconductivity gets rid of R, but R is only the real component of
the complex impedance!

The L and C components of the impedance create an LC circuit which
oscillates and radiates the 'missing' 1/2 CV^2.

Has this 1/2 CV^2 radiated energy been measured in the case of a
charging capacitor in a superconducting circuit?

--
Dave Rutherford
"New Transformation Equations and the Electric Field Four-vector"
http://www.softcom.net/users/der555/newtransform.pdf

Applications:
"4/3 Problem Resolution"
http://www.softcom.net/users/der555/elecmass.pdf
"Action-reaction Paradox Resolution"
http://www.softcom.net/users/der555/actreact.pdf
"Energy Density Correction"
http://www.softcom.net/users/der555/enerdens.pdf
"Proposed Quantum Mechanical Connection"
http://www.softcom.net/users/der555/quantum.pdf