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Check out The Feynman Lectures on Physics volume II section 40-3.
For an unadorned bullet-hole in a tank Feynman says "we are not able
to calculate" the efflux (even in the absence of significant
viscosity). If anybody can show me a simple solution to this problem
I'm going to be verrrrrrry impressed.
Even in the absence of viscosity, it's tricky to get the energy
balance _and_ the momentum balance right. The typical naive approach
is to overlook one or the other -- resulting in a plausible but
quite wrong answer.