For any non-zero mu, the ratio of the angular acceleration to the linear
acceleration is (mR) / I , independent of the value of mu.
But for mu = zero, both accelerations are zero; nothing happens. The
spinning disk stays put. The derivation, valid for non-zero mu,
encounters zero/zero.
----- Original Message -----
From: "Michael Bowen" <fizzbowen@MINDSPRING.COM>
To: <PHYS-L@lists.nau.edu>
Sent: Monday, October 28, 2002 2:23 PM
Subject: Re: When Physical Intuition Fails
| . . .but I am still having
| trouble reconciling this to the case mu = 0, which clearly has different
| behavior. I am thinking it might be instructive to analyze the behavior
in
| the limit as mu approaches zero; the amount of time required . . .
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