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Re: electrical power

Rick Tarara wrote:
...
I could try and do that at 100,000 V and 100 A, or at
100 V and 100,000 A. In both cases P = IV = 10MW. However, for whatever
the resistance of the wires delivering the power, I^2R will be quite
different.

in the expression P=IV,
V is the voltage drop across whatever
is dissipating the power. Anything
else would be grossly non-gauge-invariant.
Write it as deltaV if you prefer.