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Re: Problem



Suppose we made measurements of speed at some time increment and then
figured out d(speed)/dt numerically at the point where speed=0. What would
we get? Would it depend on the order we used (i.e., second-order vs.
n-order)?

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| Robert Cohen Department of Physics |
| East Stroudsburg University |
| rcohen@po-box.esu.edu East Stroudsburg, PA 18301 |
| http://www.esu.edu/~bbq/ (570) 422-3428 |
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-----Original Message-----
From: John Mallinckrodt [mailto:ajmallinckro@CSUPOMONA.EDU]
Sent: Tuesday, September 18, 2001 5:11 PM
To: PHYS-L@lists.nau.edu
Subject: Re: Problem

As my recent posts pointed out, in the case of a vertically
launched projectile, d|v|/dt = -g on the way up and d|v|/dt = +g
on the way down. At the top, d|v|/dt is undefined.

John Mallinckrodt mailto:ajm@csupomona.edu
Cal Poly Pomona http://www.csupomona.edu/~ajm