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Here is the calculation for -div(A), in detail, since you seem to have
trouble following the simple vector math in my original post.
....
Since E=-grad(phi) for constant v,
>>
>>I've used the same reasoning that Feynman used to derive curl(A)=vxE/c^2,
>>for constant v and E=-grad(phi) (d(A)/dt=0). If you accept Feynman's
>>derivation you _must_ accept mine.
That naughty old Maxwell! Did he forget to put that in? Well don't worry,
I've fixed it for you.