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Re: Singularity Temperature



Regarding Tim O'Odonnell's question:

It is believed that a singularity will never be observed in our Universe. If
this true, I don't think this question has any meaning since the answer would
be beyond the reach of the scientific method. Most Cosmologist believe that
the following relationship will always be true:

(G*M/(C^2))=>G(Q/C)^2+(J/M)^2 where J is angular momentum and Q is
electrical charge.

This relationship describes a Kerr Newman Black hole which is the only
type of Black hole possible (Cosmic Censor Hypothesis) which means that all
singularities produced will have their modesty protected by an event horizon.
However if the following relationship were possible you would have a naked
singularity (no event horizon) and your question could be answered by
observation.

(G*M/(C^2))<G(Q/C)^2+(J/M)^2

However there is good reason to believe this relationship is impossible. Lets
see why. Let:

(G*M/(C^2))=G(Q/C)^2+(J/M)^2 which is theoretically possible. Here we still
have an event horizon. Now one would think that by just sending charged
particles into this black hole we should be able to get the right hand side
greater than the left hand side thus creating a naked singularity that we
could observe to answer your question. However what happens when we do this
is that the electrostatic force becomes greater than the gravitational force
before we are able to get Q large enough to produce the naked singularity.
Perhaps we can increase it's angular momentum to create a naked
singularity? We could do this by sending objects with a high spin into the
black hole to increase J. However in General relativity we have an additional
force associated with an object's spin. ( Similar in character to the
magnetic force of a spinning charge) While normally this force is negligible,
in a maximally spinning black hole, this force is very significant. This
"spin-spin force" opposes the rotation of all injected objects thereby
limiting J to a value too small to create a naked singularity.
So assuming that the above is correct, than a singularity is really just
a mathematical artifact of General Relativity and can never be observed.
Therefore the question you ask has no testable answer, therefore has no
scientific meaning.

Bob Zannelli