Re: M's laws!

[Ludwik Kowalski <KowalskiL@MAIL.MONTCLAIR.EDU>]

I would find it difficult to explain M0, "Mallinckrodt's
Law of motion", as formulated by John M. (see below).

We know that acceleration is a measurable quantity.
But "a field" is not a single quantity; it is an entity
characterized by several quantities, depending on
the kind of field. And the "equivalent" is not clear.
Perhaps the wording can be improved.
Ludwik Kowalski

John Mallinckrodt wrote:

> At the (considerable) risk of appearing immodest (not to mention
> of being torn to shreds), I herewith present:
>
> "Mallinckrodt's Laws of motion"
>
> M0 = "Within *any* chosen reference frame, the gravitational field
>       at each position is equivalent to the instantaneous
>       acceleration of a freely falling particle at the same position."
>
> M1 = "The gravitational force on a particle is equal to the product
>       of the particle's mass and the gravitational field at the
>       position of the particle."
>
> M2 = N2
>
> M3 = N3
>
> Deep breath ...
> Locating fire extinguisher ...
> Sitting down ...
> Pressing "send ke