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Re: dW turns into dQ



This might be compared to asking, in F=mA, "if F includes the sum of
electrical, gravitational, etc forces and only their (vector) sum matters
for calculating A, why the partitioning?" Of course it is because this
partitioning is our way of enabling the calculation of that sum, but the
resulting A wouldn't care if you used a different partitioning (taxonomy
of F) so long as you applied the same vector sum.

Bob

Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor

----- Original Message -----
From: Joel Rauber <Joel_Rauber@SDSTATE.EDU>
To: <PHYS-L@lists.nau.edu>
Sent: Monday, November 01, 1999 12:50 PM
Subject: Re: dW turns into dQ


. . .
If the partitioning is totally arbitrary once a specific process and
time-scale is determined, why bother partitioning at all?
. . .
Joel