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Re: Alternating Current



Jack,
I think you'd better re-think this argument.
You may have both Heisenberg and Nyquist rolling over in their graves!
(Or do I mis-read you?)
Certainly I can measure the frequency of .01sec of a 120Hz signal (say on a
scope) to better than an error of 100Hz!

Bob Sciamanda
Physics, Edinboro Univ of PA (ret)
trebor@velocity.net
http://www.velocity.net/~trebor

-----Original Message-----
From: JACK L. URETSKY (C)1998; HEP DIVISION, ARGONNE NATIONAL LAB ARGONNE,
IL 60439 <JLU@HEP.ANL.GOV>
To: PHYS-L@LISTS.NAU.EDU <PHYS-L@LISTS.NAU.EDU>
Date: Friday, January 29, 1999 10:08 PM
Subject: Re: Alternating Current


Hi all-
As others have pointed out, David is sampling the power,
so that his "expected result" is 120 HZ, not 60 Hz. Now let's understand
why he got 124 Hz instead of 120, given that the power company makes
clocks run on time. Following Brian's comment, let's estimate the
uncertainty in David's result.
David used a sampling interval of 10^-4 s, and took 100 data
points.
He therefore sampled over a time interval of 10^-2 s. What was the
precision
of his result? Aha, the uncertainty principle rears her pretty head:
(delta t)*(delta f) = 1
But delta t = 10^-2 s (according to David's message) so delta f can be
no better than 100 Hz. How can this be if David sees 124 Hz with good
precision?
It can't. Either David's precision is much worse than he thinks
or there was a typo in his report of a sampling interval. If the sampling
interval was 10^-3 instead of 10^-4, then he sampled over a time interval
of 0.1 s, and recorded about 8 cycles. His uncertainty was then ~10 Hz,
and 124 Hz is a reasonable estimate of the "expected value" of 120 Hz.
Regards,
Jack
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