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Re: radiometer paradox



Joseph Gress wrote:

I am puzzled by how a radiometer works. It makes sense to me that
when you shine light on the black fin that radiation pressure would
cause the radiometer to spin. However, why doesn't it spin even
faster when you shine light on the white fin? In fact, it doesn't
spin at all! If I think of
reflection as a photon of light bouncing off of the white
fin, then the change in momentum of the photon would be twice as
great as if the photon were absorbed.

I looked up radiation pressure in several text books. The closest
example indicated that radiation pressure = the light irradiance
(watts per m^2) / speed of light; i.e. P=I/c if the light is
completely absorbed whereas P=2I/c if the light is reflected. This
matches my simple picture of what I thought was happening when light
hits the radiometer fins.

So, why doesn't light shining on the white fin (which is reflected) cause it to spin
faster than light shining on the black fin (which is absorbed).

Joseph Gress
**************************************

Sincerely,
Joseph Gress
Department of Physics and Astronomy
Moorhead State University
Moorhead, MN 56563
e-mail: gress@mhdha.moorhead.msus.edu

Joseph,
You are speaking of the Crookes Radiometer. Conventional Wisdom treats
this as a thermal phenomenon. The container is NOT a high vacuum. The
blackened side of the vane absorbs better than the reflective side and
so attains a slightly higher temperature. The result is a higher air
(not radiation) pressure on the blakened side. I'm sure that Jearl
Walker's "Circus" book gives more details and references for this - I
don't have it handy. (In a high vaccuum, the radiation pressure would
dominate, and your expectation would be realized.)
--
Bob Sciamanda sciamanda@edinboro.edu
Dept of Physics sciamanda@worldnet.att.net
Edinboro Univ of PA http://www.edinboro.edu/~sciamanda/home.html
Edinboro, PA (814)838-7185