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Re: [Phys-L] field of an ellipsoidal distribution



Given a perfectly spherical and homogeneous earth, the horizontal component of the centrifugal force would move earth stuff toward the equator, reshaping the earth's profile so that the normal force of rigidity can now, by itself, completely cancel both the gravitational and centrifugal forces.

-----Original Message----- From: Chuck Britton
Sent: Saturday, August 15, 2015 7:46 PM
To: Phys-L@Phys-L.org
Subject: Re: [Phys-L] field of an ellipsoidal distribution

If your table were floating on the surface of a (quiet) lake, the water would not feel a (net) force toward the equator, nor would your air puck.

Right?

On Aug 15, 2015, at 3:41 AM, Bob Sciamanda <treborsci@verizon.net> wrote:

Forget the table and consider the forces on the material of the earth surface itself. It is this "horizontal" component of the centrifugal force which moves earth stuff towards the equator to produce the bulge.

-----Original Message----- From: Bob Sciamanda
Sent: Friday, August 14, 2015 2:47 PM
To: Phys-L@Phys-L.org
Subject: Re: [Phys-L] field of an ellipsoidal distribution

Given a perfectly spherical rigid earth, and a table whose horizontal
surface is perpendicular to the earth radius, the centrifugal force on an
object resting on this horizontal surface has a horizontal component (very
small in the real situation).

-----Original Message----- From: Carl Mungan
Sent: Friday, August 14, 2015 2:37 PM
To: PHYS-L
Subject: Re: [Phys-L] field of an ellipsoidal distribution

Hmm… define what you mean by a “horizontal” tabletop. Are you telling me
that I should not expect a puck placed on a horizontal air hockey table to
remain at rest?

On Aug 14, 2015, at 2:22 PM, Bob Sciamanda <treborsci@verizon.net> wrote:

Carl wrote:
"The YouTube video neglects a small correction by assuming that N points in the
radial direction. This is the old question of “which way does a plumb bob
point” on a rotating earth point? . . .

Interesting ... My spin is that the You Tube guy is not thinking of a plumb bob - he is modeling an object resting on a horizontal table top at the earth's surface. Then his calculated N is indeed the normal force of the table top on his test object. In addition there is required a frictional force from the table top to balance the horizontal component of the centrifugal force.
For a hanging bob model, the string must supply both components, as a single tension force (T, not N).

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net
www.sciamanda.com
_______________________________________________
Forum for Physics Educators
Phys-l@www.phys-l.org
http://www.phys-l.org/mailman/listinfo/phys-l


-----
Carl E Mungan, Assoc Prof of Physics 410-293-6680 (O) -3729 (F)
Naval Academy Stop 9c, 572C Holloway Rd, Annapolis MD 21402-1363
mailto:mungan@usna.edu http://usna.edu/Users/physics/mungan/

_______________________________________________
Forum for Physics Educators
Phys-l@www.phys-l.org
http://www.phys-l.org/mailman/listinfo/phys-l

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net
www.sciamanda.com

_______________________________________________
Forum for Physics Educators
Phys-l@www.phys-l.org
http://www.phys-l.org/mailman/listinfo/phys-l

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net
www.sciamanda.com
_______________________________________________
Forum for Physics Educators
Phys-l@www.phys-l.org
http://www.phys-l.org/mailman/listinfo/phys-l

_______________________________________________
Forum for Physics Educators
Phys-l@www.phys-l.org
http://www.phys-l.org/mailman/listinfo/phys-l

Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
treborsci@verizon.net
www.sciamanda.com