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Re: [Phys-L] A suspended metal rod



Nothing wrong with the question. The torque equation will tell you where the center of mass of the rod is. However, it is probably easy to make an unwarranted assumption about the position of the CM and get inconsistent answers.

John Mallinckrodt
Cal Poly Pomona

On May 11, 2013, at 5:34 PM, LaMontagne, Bob wrote:

I really put my foot in it on this one.

I needed a quick exam question related to equilibrium - so I made up the following:

A 10 kg metal bar of length 1 meter is suspended in a horizontal position by two mass-less cables attached to its ends. Cable 1 makes a 30 degree angle with the axis of the rod and cable 2 makes a 60 degree angle with the axis of the rod. What are the tensions in the two cables? (I didn't really write the question out this way - I drew a diagram that was equivalent - can't draw a diagram on the list.)

I ran a quick analysis using the sum of the forces in the x and y directions, checked my results, and they appeared to work. Many of my best students agreed with my answers. However, two of my best students got a different answer for the tensions - and they agreed with each other. I checked their results and their arithmetic was fine. However, they solved the problem using torques about the two ends of the rod.

It took me a quite few minutes to figure out what was wrong - and I was quite embarrassed. The moral of the story is don't make up quickie problems for an exam.

Bob at PC
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