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Re: [Phys-L] gravity + tunneling to the antipodes

That will depend entirely on your latitude.

You would need:
m g = m r w^2

The radius (r) will be your distance from the earth's axis. At the equator that will be about 6E6 meters.

w^2 = 6e-5

w = 0.0077 / s

Which works out to about 666 times faster than the earth currently spins. Of course, it wouldn't hold its shape. Water would rush to the equator where it would easily fly off into space.

Paul



On Jan 3, 2013, at 12:57 PM, Robert Cohen <Robert.Cohen@po-box.esu.edu> wrote:

P.S. Here's a question: how fast does the Earth have to spin such that
the dropped object doesn't make it through the tunnel but instead pops
back up out the hole?