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Suppose you have two non-rotating Earth's with a center to center
distance of 3 Earth radii. What gravitational field (in terms of g,
the gravitational field on an isolated non-rotating Earth) would be
determined by a person standing at the point on the surface of one
of the Earths that is closest to the other Earth? Is it the same as
the acceleration that person observes for an object dropped to the
ground?
Thanks for biting. My guess is that some folks would claim that the
gravitational field "at that position" is 3/4 g toward the ground.
The observed acceleration of freely falling objects in a frame
attached to that position however is 31/36 g toward the ground. In
my world that means that the gravitational field in that frame is
31/36 g.
Note that I didn't say and you certainly shouldn't assume
that the Earths are (somehow!?) *held* with their centers 3 Earth
radii apart.