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Re: [Phys-l] App. for Was: Re: T dS versus dQ



Bob LaMontagne wrote:

With the hope that I won't get shouted down for daring to mention this topic again, may I respond to JM's quoted comment:


I promise; no shouting. ;-)

But how excruciating must the detail be? If one envisions a cylinder that is absolutely impervious to any energy transfer through its walls, fitted with a piston and containing Nitrogen only, and a stop inside the cylinder that prevents the piston from compressing the gas to less than half its original volume - and then one applies a force with one's hand to push the piston to the stop in 10 seconds - and then repeat with identical apparatus but do the compression in 0.001 seconds, and then let the two pieces of apparatus sit for a while until all waves. etc., dissipate, will there be any difference in their final states

Yes.

- and specifically what?

I can't say, and only in part because you haven't provided nearly enough detail. At the very least you'd have to know the precise function x(t) that describes the position of the piston as it compresses the gas, but that certainly wouldn't be enough. In addition you'd need to know the detailed shape of the cylinder so that you could get a handle on how the disturbance propagates through the gas and back to the piston again. But even once you provided enough information, calculating the precise amount of work done from first principles would be *very* tough sledding; I dare say impossible.

The final volumes are identical, will the final temperatures and pressure be higher?

Both will be higher than they would have been had the process been quasistatic. This is a simple deduction from the fact that the entropy will be higher because of the fact that dissipation has occurred. They will also almost certainly be different.

If this is not a sufficient specification of process and boundary conditions, what else need be specified?

See above.

JM

On 2010, Jan 20, , at 11:04, John Mallinckrodt wrote:


It's interesting to me that the analysis of the rapid versus slow
compression of a thermally insulated gas can cause so much confusion
and I think the reason has to do with the fact that it can't be
easily done by simply talking about work and energy (and it can't be
done *quantitatively,* period, without knowing about the process and
the boundary conditions in excruciating detail.) By considering
things like the potential energy loss of a heavy piston as it falls
or the kinetic energy added to and then delivered by the piston, it
can be tempting to suppose incorrectly that the rate of the process
is irrelevant to the final state.