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Speaking of: You all know the mass of a simple pendulum's bob (a physical >also) serves both as an inertial mass, as in a spring oscillator, and also as a >gravitational mass (a non-linear spring). Since Eötvös, they are the same. >However, they are not the same if the pendulum is not so simple. I mean when >the bob is immersed in a fluid. A minor matter if the bob is in air (Horologists, >correctly disagree.), but always a serious matter if the fluid is water. Pray tell, >how does one write the diff. eq. to make the correction. I've done this, and its >solution disagrees w/ the horological lit. Perhaps I've done it correctly and the >horological correction is an approximation or I'm too maths challenged to >convert.