The only 'behavior' that I can see is that the volume of water is
still in equilibrium so the net vector force on it's surface equals
its weight.
I agree, if the cube is water. Maybe I misinterpreted your situation. However, if it's not water, this conclusion isn't (I think) generalizable.
jg
At 3:34 PM -0400 11/5/10, Chuck Britton wrote:
>At 3:23 PM -0400 11/5/10, Josh Gates wrote:
>>_____
>>
>>From: Chuck Britton [mailto:cvbritton@embarqmail.com]
>>
>>
>> It seems to me (naively) that we better come up with exACTLY the same
>> total force when we integrate force around all SIX sides of this
>> mathematical volume as we did the first time.
>> That only follows if the behavior of the cube is the same as
>>before - that it floats or sinks or stays with the same accel. as
>>before. If it stays on the bottom now instead of accelerating
>>upward, then I don't agree.
>
>
>It's a mathematical construct. It doesn't beHAVE in any way except as
>the axioms and postulates of whatever maths you are using calls for.
>_______________________________________________
>Forum for Physics Educators
>Phys-l@carnot.physics.buffalo.edu
>https://carnot.physics.buffalo.edu/mailman/listinfo/phys-l