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I think there is no force on any particle anywhere in the
cavity, so (C).
Crawford
On Mon, 4 Oct 2010 14:04:45 -0400
"Brian D. Shock"<Brian.Shock@powhatan.k12.va.us> wrote:
Sounds like the net force acting on the ball before and
after is zero, so no change in the r. Is there a
temperature change?
Brian Shock
Physics
Rm 2028
598-5710 ext 225
-----Original Message-----
From: phys-l-bounces@carnot.physics.buffalo.edu on behalf
of Fakhruddin, Hasan
Sent: Mon 10/4/2010 1:31 PM
To: Forum for Physics Educators
Subject: [Phys-l] Clarification: A ball at the center
of a planet
Alright folks, Here is a little modification:
A solid elastic rubber ball is a perfect sphere of
radius r in free space. A solid homogeneous spherical
massive run away planet also in free space has a
spherical cavity formed at its center. The cavity is
much larger than the ball and has vacuum in it. The ball
is now transported to the center of the planet. Its
radius now is
(A)> r
(B)< r
(C) = r
(now come on....don't ask me to define free space)
How did you guys ever take any exam without giving your
instructor ulcers?!
'Burp'....excuse me; I just took Alka-Seltzer!
~ Hasan Fakhruddin