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Re: [Phys-l] Conservation of energy in nuclear reactions




In a message dated 5/1/2009 3:21:31 PM Eastern Daylight Time,
Spinozalens@aol.com writes:


In a message dated 5/1/2009 3:12:19 PM Eastern Daylight Time, Spinozalens

writes:


On Friday, May 01, 2009 11:54 AM, John Denker wrote:

Part of the energy is mc^2. We call this the _rest energy_.
I suppose you could define potential energy to be equal to
the rest energy, but not everybody does. Also there are
issues with the gauge-dependence of typical notions of
potential energy.

OK

Let's be clear: The equation E=mc^2 applies in the rest
frame of the particle. This is Einstein's original meaning
of the equation, and also the meaning that has been
conventional among those who do relativity for a living, and
has been for several decades that I know of. (I am aware
that from time to time there have been attempts to define
some notion of "relativistic mass", but this is a Bad
Idea./2/) Mass (m) means rest mass, so it is redundant but
harmless to call it "rest" mass.

Agreed.

Bottom line: Energy is conserved. Period. There are no
known exceptions. Of course to make this work you need to
include all forms of energy, including the rest energy mc^2.

Still, the question is whether this form of energy is *in addition to*
the energies we considered previously (like the gravitational energy or
whatever) or *instead of*. That is what I am confused about and how I
could simply explain this to non-scientists.

Consider an astronaut dropping a rock on the moon. While the rock is
falling, how does the kinetic energy of the moon/rock/astronaut change?
How does the rest energy of the moon/rock/astronaut change? Are there
any other forms of energy that are changing?





))))))))))))))))))))))))))))))))))))))))

The energy of the rock is constant before it hits the surface. Being held

above the surface it has all of its energy as potential energy. (
ignoring
thermal, etc.) As it falls it converts its potential energy to kinetic ene
rgy of motion, the sum of the kinetic and potential being constant. (
Hamiltonian) When it hits the surface all of former energy of motion (at
this
point is has zero potential energy) is converted to molecular energy
(heat,
sound, etc.) Energy is conserved at all times.

Bob Zannelli







This ignores air friction which will actually cause some of rock's energy
to be converted to molecular energy, heat, sound.


Bob Zannelli






Oh the moon. No air, never mind.

Bob Zannelli
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