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-----Original Message-----
From: phys-l-bounces@carnot.physics.buffalo.edu [mailto:phys-l-
bounces@carnot.physics.buffalo.edu] On Behalf Of paul beach
Sent: Thursday, October 23, 2008 11:02 PM
To: phys-l@carnot.physics.buffalo.edu
Subject: [Phys-l] How much energy can a battery discharge
How much energy can a Battery Hold? Can I just divide grams-moles by
Coulumbs?
1 Coulumb = 6.2 x 10^18 electrons or 1 A / sec
Avogadro's number = 6.02 x 10^23 gram-moles
Coulumbs for a gram-mole = 6.02*10^23 / (6.2*10^18)
= 97096.77419
Divide by 60*60 to get amp hours = 26.97132616
Therefore something the size or mass of a sugar cube, could give about
27 amp hours on the negative terminal.
--
paul beach
sniffyraven@fastmail.fm
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