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I agree with Jeffrey's as the best solution. In my mind there is a huge
conceptual difference between a(g) and g. It is a wonderful point of nature
that they are numerically equal and even the units are equivalent (pun
intended). I tweak the brain by indicating that one day they will appreciate
this coincidence.
ma(g) = mg two concepts of mass are at work here as well.
One hard thing about this is conflicting with the text book or web
resources.
Ken Fox
On 9/17/07, Jeffrey Schnick <JSchnick@anselm.edu> wrote:
_______________________________________________
I use a_g = 9.8 m/s^2 for the acceleration of an object in freefall near
the surface of the earth and g = 9.8 N/kg for the magnitude of the
earth's near-surface gravitational field.
> -----Original Message-----
> From: phys-l-bounces@carnot.physics.buffalo.edu
> [mailto:phys-l-bounces@carnot.physics.buffalo.edu] On Behalf
> Of Rauber, Joel
> Sent: Monday, September 17, 2007 9:34 AM
> To: phys-l@carnot.physics.buffalo.edu
> Subject: [Phys-l] PER folks and units of g
>
> This is mostly addressed to the PER gurus, but others should
> need no invitation to chime in, as their experience is
> appreciated and valuable.
>
> There was a post a while back that suggested that the PER
> research was indicating that it is best to quote g as follows:
>
> g = 9.8 N/kg rather than g = 9.8 m/s^2
>
>
> the question I have is following a traditional sequence of
> kinematics first, while introducing free-fall what do you
> suggest for g?
>
...
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