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Re: [Phys-l] (no subject)



My guess is your algebraic expression for 'r' is probably Sqrt(x^2 + P^2), but that doesn't give you the correct r for negative x values. You'll need to use something like r = sqrt((L-x)^2+p^2).

See if that's the problem. If not, give more details.

Rick

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Richard W. Tarara
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Saint Mary's College
Notre Dame, IN
rtarara@saintmarys.edu
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----- Original Message ----- From: <pschoch@nac.net>
To: <phys-l@carnot.physics.buffalo.edu>
Sent: Tuesday, February 27, 2007 11:49 AM
Subject: [Phys-l] (no subject)


Greetings,

I am trying to solve a problem asked of me by the class, and am
having a bit of trouble...

I solved the E field problem of a finite line of charge on the x axis
from -L to 0, at a point (0,P).

One young man took an example from the textbook, tried to combine it with
my example, and got a solution that makes no sense and asked if I could do
it.

After trying, I also get something that doesn't seem right, and I need a
bit of help doing this with only freshman techniques. The problem is:

You have a line of charge from (-L,0) to (L,0), and a point at
(-L,P). Evaluate the E field at the point (L,P).

When I try to do this by Freshman physics methods and evaluate the
line integral to get the x and y components from the line of charge I get
the x component to cancel out (because of the integration from -L to +L).
Now, this can't be correct, but I don't see my error.

Any help would be appreciated.
P. Schoch


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