Re: [Phys-l] Disc polarizability

[Bernard Cleyet <bernardcleyet@redshift.com>]

Jerry!

Panzer(s).  However, my interest is w/ the E direction parallel w/ the 
disk, and more  importantly the derivation.  The latter only for my 
curiosity.  Having a reasonable expression will allow me to derive the 
index of an array of discs at very low (compared to optical) frequencies.

bc, used emu and esu units in the 50's, not since, and suspects JF got 
his answer from a text BSI, and (bc) let the cat outa the bag.

Jerry Franklin wrote:

> For a disc, perpendicular to a field E, there is an induced surface charge
> (in gaussian units) sigma=+E/4 pi on one face and minus that on the other.
> The dipole moment for this charge distribution is sigma X A X t for area A and
> thickness t of the disk.  This gives p=sigma X Volume=E V/4pi.
> Thus the polarizability is Volume/4pi in gaussian units.   
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