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Re: [Phys-l] Weightless (running around in circles)



Suppose I established a coordinate system and took some position vs.
time measurements on the object that has the accelerometer attached to
it. Further suppose that, from that data, I determined the acceleration
of the object, call it r double dot, relative to the established
coordinate system. I understand r double dot to be the what NIST calls
"the local acceleration of free fall in that reference frame." Is the
NIST definition of weight just how hard and which way I would have to
push on the object to make its accelerometer reading be r double dot?

The NIST definition is the one at
http://physics.nist.gov/Pubs/SP811/sec08.html
NIST>In science and technology, the weight of a body in a particular
NIST>reference frame is defined as the force that gives the body an
NIST>acceleration equal to the local acceleration of free fall in that
NIST>reference frame [6: ISO 31-3].


-----Original Message-----
From: phys-l-bounces@carnot.physics.buffalo.edu [mailto:phys-l-
bounces@carnot.physics.buffalo.edu] On Behalf Of John Mallinckrodt
Sent: Wednesday, November 22, 2006 3:58 PM
To: Forum for Physics Educators
Subject: Re: [Phys-l] Weightless (running around in circles)

On Nov 22, 2006, at 12:11 PM, Jeffrey Schnick wrote:

So if I strapped an ideal accelerometer to an object, the weight of
the object would be the product of its mass and the magnitude [of]
its accelerometer reading?

Yes. That's what I'd want to say.
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