Re: [Phys-l] momentum and energy

[Bernard Cleyet <bernardcleyet@redshift.com>]

Bob!

As DCI Foyle would say, "good".

Panzer,

bc

Bob Sciamanda wrote:

> If you impose both momentum and kinetic energy conservation on a one 
> dimensional collision between m(initial velocity v) and M(initially at 
> rest), you easily see that in the limit as M/m increases without limit:
> 1) the final velocity ( V ) of M approaches a limiting value of zero, BUT
> 2) The product MV (M's final momentum) approaches a definite limit, equal to 
> 2mv (twice m's initial momentum),
> 3) As a RESULT of the above it follows that the final KE of M =  (1/2) 
> (MV)(V) approaches the limit of ZERO, since the limit of MV is finite and 
> definite, while  the limit of V is zero.
>
> Bob Sciamanda
> Physics, Edinboro Univ of PA (Em)
> http://www.winbeam.com/~trebor/
> trebor@winbeam.com
> ----- Original Message ----- 
> From: "Bernard Cleyet" <bernardcleyet@redshift.com>
> To: "Forum for Physics Educators" <phys-l@carnot.physics.buffalo.edu>
> Sent: Tuesday, November 14, 2006 11:43 PM
> Subject: Re: [Phys-l] momentum and energy
>
>
>  
>
> > Classically (N)  p^2/2m = (identically)  m^2* V^2 / 2 m    Am I crazy?
> >
> >
> > If not, then,  lim:  m => inf.      (with v non zero*)   E => .    not 
> > zero
> >
> > * Which I think agrees w/ jsd ==  i.e.  "you will find that V makes a
> > negligible contribution to the golf ball velocity, but a nontrivial
> > contribution to the conservation law."
> >
> > Negligible is not zero?
> >
> > ___
> >
> > bc, missing something?
> >    
>
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