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here goes:
What I'm getting from the problem description is that there's a vertical
wall (WLOG, put this on the left) and an inclined plane going from lower
left to upper right, theta above horizontal. The forces on the ball are:
gravity - mg down
force of wall - directed horiz. to right
force of inclined plane - directed normal to plane, towards upper left of
diagram.
net force on ball vanishes in all directions.
In particular, choosing right and up as positive,
Fnet, x = Fwall - Fplane sintheta = 0
Fnet, y = Fplane costheta - mg = 0
from this,
Fplane = mg/cos theta
and
Fwall = mg tantheta
dividing out mg gives Feynman's solution.
jg
Forum for Physics Educators <phys-l@carnot.physics.buffalo.edu> on
Wednesday, August 02, 2006 at 4:49 PM -0500 wrote:
I have just finished reading "Feynman's Tips on Physics" and found it very
enjoyable. Then I got to the problems at the end of the book and the
first one intrigued me.
A Ball of Mass = 1 kg and radius of 3 cm is resting on an inclined plane
against a wall, the incline is at an angle alpha. The question is to find
the force from the incline and the wall on the ball assuming negligable
friction.
Hubris is a terrible thing. Thinking this was trivial, I plunged into the
problem and got nowhere near the solution in the text:
F(plane)= 1/cos(alpha)
F(wall) = tan(alpha).
I get (leaving mass unknown and g in the equations):
F(plane) = Mg cos(alpha)
F(wall) = 0.5Mg sin(2*alpha)
Any help in where I went awry would be appreciated.
Peter Schoch
Sussex CC
_______________________________________________
Forum for Physics Educators
Phys-l@carnot.physics.buffalo.edu
https://carnot.physics.buffalo.edu/mailman/listinfo/phys-l
_______________________________________________
Forum for Physics Educators
Phys-l@carnot.physics.buffalo.edu
https://carnot.physics.buffalo.edu/mailman/listinfo/phys-l