Re: [Phys-l] Blackbody radiation

["Bob Sciamanda" <trebor@winbeam.com>]

I think the argument is from thermodynamic principles and asserts that the 
energy spectrum of a black body in equilibrium with a definite temperature 
environment should be independent of the details of its structure.  Thus in 
calculating the universal BB spectrum function dE(lamda) one is free to 
choose any valid BB construction for the calculational model.
Bob Sciamanda
Physics, Edinboro Univ of PA (Em)
http://www.winbeam.com/~trebor/
trebor@winbeam.com
----- Original Message ----- 
From: "Michael Edmiston" <edmiston@bluffton.edu>
To: "PHYS-L Maillist" <phys-l@carnot.physics.buffalo.edu>
Sent: Wednesday, May 17, 2006 9:09 AM
Subject: [Phys-l] Blackbody radiation


> . . .
> First of all, hot objects that are not cavities will emit radiation that
> is nearly BBR.  That is, the cavity is not really necessary for getting
> the basic BBR curves.  The sun is not a cavity radiator.  So what do
> standing waves have to do with BBR from hot objects that don't have
> cavities?
> . . .
> Michael D. Edmiston, Ph.D.
> Professor of Physics and Chemistry
> Bluffton University
> Bluffton, OH 45817
> (419)-358-3270
> edmiston@bluffton.edu