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If the material being heated is thin (like
paper) energy distributed by conduction would exit from the spot with
circular symmetry, that is, proportional to the circumference of the
spot. If you decrease the spot diameter by two, you increase the power
density by four, and you decrease the conductive path by a factor of
two. That seems like a win-win. If the material is thicker so that the
conduction is into "2pi", then decreasing the spot diameter by two
increases the power by four and decreases the conductive path by four.
That seems like win-biggerwin.
It would appear to me that if conductive losses are bigger for smaller
spots, it would have to be driven by the temperature difference
(delta-T), not by geometry factors. The geometry factors appear to
favor the small spot.
Michael D. Edmiston, Ph.D.