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On Feb 20, 2006, at 10:24 AM, John Denker wrote:
> It must be emphasized that the arrow in this situation does not
> represent i itself; the arrow represents a _basis vector_. The
> actual current is some multiple of this basis vector.
Current is a vector????? Current density is, but not current.
Vern Lindberg
vern.lindberg@rit.edu
585-475-2546
http://www.rit.edu/~vwlsps/