|
| Joel wrote:
|
| | . . .The key is realizing that its not cancellation in the sense
| | operating with the inverse on both sides of the equation. . . .
|
| You confuse me:
| Are you implying that there exists an operator "O" (the
| "inverse" of the operation Cvec DOT) such that O(Cvec DOT
| Avec) yields the vector Avec?
|
I don't mean to imply that, if it were ordinary mutliplication,
"canceling" implies dividing both sides by C, that is the inverse of
multiplication, hitting the l.h.s of
C*A=C*B with C^(-1)
That's all I meant.
Of course it isn't ordinary multiplication . . . (hence the discussion)
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