JM wrote:
| . . .
| Just yesterday I had every student in a junior E and M class tell me
| that, if Cvector dot Avector = Cvector dot Bvector for any Cvector
| then we can cancel the Cvector on both sides of the equation and
| determine that Avector = Bvector. That is the right answer, and the
| argument is appealing, but it is, nevertheless, wrong.
| . . .
Perhaps they were inferring "for any Cvector" to mean "for any and all
possible Cvectors"