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[Phys-L] Re: centripetal force question



I've been thinking about this more after reading some of the insightful
responses. So then the rider pushes down (slanted) on the seat/cycle. This
adds a slanted downward force component to the cycle. So for the cycle,
this y-component is downward (making N larger), and the x-component goes
opposite to the frictional force, making the net horizontal force smaller.
Right?
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