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[Phys-L] Re: Weighing air (Was: electricity)



Perhaps I had better go into a few more details.
I expect any pressure vessel to stretch elastically, and hope not to
stray into the pressures where its expansion becomes non-linear.

Why is the calculated density of air that I produced less than the
accepted value? The considerable expansion of the vessel should
give an apparent density greater than the benchmark

I was of course doing the demonstration at room temperature
where the density value benchmark is given at 0 degC

This accounts for a difference of about 293/273 or 1.07
Multiplying my number by this ratio does indeed place the density
too high.

Brian Whatcott

At 09:58 PM 2/5/2005, bc, you wrote:

[Brian]
"Major uncertainty was the volume of the bottle."


I thought so to until I plotted your (BW) data. I expected it to curve
as a result of expansion of the bottle under increasing pressure.
Instead a linear plot is a better fir than a power one. Not only that,
the exponent is sl. less that one!

bc



Brian Whatcott wrote:

Weighing an air bottle:

data
air temp 20degC, ambient pressure 29.93 in Hg
bottle wt full = 2.2 kg
empty = 75.9 gm
volume = 2.124 liter

air
press
psig bottle wt gm
32 81.8
25 80.4
19 79.5
17 79.3
15 78.6
12 78.1
9 77.6
0 75.9

Least squares fit
weight = [75.94 +-0.09] + air pressure X [0.183 +- 0.005] gm

For an air pressure of 14.7 psig excess wt is 0.183 X 14.7 gm
= 2.69 gm for 2.124 liters
= 1.266 gm/liter This is fairly respectable.
Major uncertainty was the volume of the bottle.

Brian Whatcott Altus OK Eureka!





Brian Whatcott Altus OK Eureka!