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-----Original Message-----
From: Ludwik Kowalski
Sent: Friday, May 07, 2004 11:49 AM
Subject: Re: Internal resistance again.
I am using a d.c. power supply to pass a current
through an Al foil. From the positive of the power
supply the current goes through the ammeter
and through the foil (firmly squeezed between
two metallic plates). The voltage is measured
between these plates. I expected voltage to be
I*R but it is not.
I=1.3 A --> 0.55 volts
I=2.0 A --> 1.06 volts
I=2.9 A --> 1.30 volts
How can this be explained? I am sure that R
is essentially constant. The impedance of the
voltmeter is certainly much larger than 1 ohm.