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Re: TdS is not dQ or d(anything)



"John S. Denker" wrote:


This analogy is very, very tight. If state space
is two-dimensional (e.g. spanned by T and V) then
dP at each point in that space can be represented
by non-square matrix (one row and two columns) that
says: give me an input vector (specifying the
direction and magnitude of a step in state space)
and I'll give you a scalar which is the change in
P that results from that step.

I'm still missing how dP is a state function. If I give your machine two
different sets of input vectors, I get two different scalar dp values. How do
you reconcile this lack of uniqueness with a state function?

Bob at PC
Who submitted his last semester grades today :-)