Re: Capacitor energy experiment

[David Rutherford <drutherford@SOFTCOM.NET>]

Bob LaMontagne wrote:
> David Rutherford wrote:
>
> > Thus, for a capacitor charged through a resistance, the energy
> > dissipated by the resistor during charging should be included, along
> > with the energy of the charges stored on the capacitor, in the energy
> > of (work done on) the charges. Since the energy dissipated by the
> > resistor during charging is 1/2 CV^2 and the energy stored on the
> > capacitor is 1/2 CV^2, I claim that the total energy of the charges,
> > in the absence of dissipation would have been CV^2. This would seem to
> > indicate that the energy of a distribution of charges is twice the
> > conventional value.
>
> OK - so you've redifined the value of the stored energy. Now describe a way
> to get CV^2 of useful work from the capacitor. Make it specific enough so
> the method could be performed by those so inclined.

You won't get CV^2 of work from the capacitor, alone. As I stated above,
the energy stored on the capacitor, in the presence of a resistance, is
only 1/2 CV^2. The other 1/2 CV^2 of energy is dissipated as heat in the
resistor during the charging of the capacitor. Therefore, the total work
derived would have to be a combination of the work derived from the heat
dissipated by the resistor during the charging of the capacitor, and the
work derived from the energy stored on the capacitor.

--
Dave Rutherford
"New Transformation Equations and the Electric Field Four-vector"
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