Re: There's work, and then there's work

[David Rutherford <drutherford@SOFTCOM.NET>]

Hugh Haskell wrote:
> At 17:20 -0800 2/2/03, David Rutherford wrote:
> > If this is true, doesn't it imply that, when the capacitor is
> > discharged, only half of the energy stored on the capacitor will be
> > dissipated as heat in the resistor, therefore, the calorimeter
> > experiment would only give _half_ of the energy stored on the capacitor?
> Assuming that the author of the quote you cite means what he appears
> to have said (which I doubt), do you have a suggestion for a home for
> the half of the energy that appears, by this statement, to be missing?

When the capacitor is charging, half of the energy of the charges is
dissipated as heat in the resistor and the other half goes into the
charging of the capacitor. So it's logical to assume that, when the
capacitor discharges, half of the energy of the charges is dissipated as
heat in the resistor and the other half goes into the discharging of the
capacitor.

--
Dave Rutherford
"New Transformation Equations and the Electric Field Four-vector"
http://www.softcom.net/users/der555/newtransform.pdf

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"Proposed Quantum Mechanical Connection"
http://www.softcom.net/users/der555/quantum.pdf