"From the definition of voltage as the energy per unit charge, one might
expect that the energy stored on this ideal capacitor would be just QV.
That is, all the work done on the charge in moving it from one plate to
the other would appear as energy stored. But in fact, the expression
above shows that just half of that work appears as energy stored in the
capacitor. For a finite resistance, one can show that half of the energy
supplied by the battery for the charging of the capacitor is dissipated
as heat in the resistor, regardless of the size of the resistor."
If this is true, doesn't it imply that, when the capacitor is
discharged, only half of the energy stored on the capacitor will be
dissipated as heat in the resistor, therefore, the calorimeter
experiment would only give _half_ of the energy stored on the capacitor?