Re: There's work, and then there's work

[David Rutherford <drutherford@SOFTCOM.NET>]

Bob LaMontagne wrote:
> More explicitly, what the students do in the lab is the following: They measure the
> slow discharge of the capacitor through a resistor, R. They record the current at
> regular time intervals, dt, say 5 seconds. They then graph the current as a function
> of time and obtain the total charge.

Why don't you assume that an equal amount of opposite charge flows in
the opposite direction. That would double the total charge and make the
energy equal to CV^2, not 1/2 CV^2. If the answer is no, please explain
why not (Obviously, I'm rethinking my claim that my theory gives 1/2
CV^2 and that 1/2 CV^2 is the correct answer).

--
Dave Rutherford
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