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A student of mine was thinking about hydraulic systems and brought in=
his floor jack. We measured the diameter of the input and output pi=
stons and the distance each moved during one pass. We hoped that the=
total volume would be the same, i.e., pi r2 h of one would equal pi =
r2 h of the other, where h is the distance each piston moved during o=
ne pass. However, the output volume is 20-25% greater.
Anyone know what we're missing?
____________________________________________
Robert Cohen; rcohen@po-box.esu.edu; 570-422-3428; http://www.esu.edu=
/~bbq
Physics, East Stroudsburg Univ., E. Stroudsburg, PA 18301