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2 pi i = 0



A student showed me a proof of the relationship 2*pi*i=0 this morning. The proof went:

e^(2*pi*i)=1

e^0=1

e^(2*pi*i)=e^0

take ln of both sides

2*pi*i = 0

Something seems fishy about this to me. But I don't know what.

Comments?

This posting is the position of the writer, not that of SUNY-BSC, NAU or the AAPT.