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2 pi i = 0
From
: Justin Parke <
FIZIX29@AOL.COM
>
Date
: Fri, 22 Nov 2002 10:03:18 -0500
A student showed me a proof of the relationship 2*pi*i=0 this morning. The proof went:
e^(2*pi*i)=1
e^0=1
e^(2*pi*i)=e^0
take ln of both sides
2*pi*i = 0
Something seems fishy about this to me. But I don't know what.
Comments?
This posting is the position of the writer, not that of SUNY-BSC, NAU or the AAPT.
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