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When the mass is hung on the spring, the spring stretches by an
amount d = mg/k. (Non-conservative work was done by your hand taking
the mass to the equilibrium point - otherwise the mass would
oscillate!)
If we call this position x=0 and now pull the mass downward by an
additional amount, x, the potential energy term is 1/2 k (d + x )^2
- m g x. Because of the cross term in the square, 1/2kx^2 does not
seem to take on any easily identifiable meaning (at least not for an
introductory physics class).
Perhaps someone out there has thought about this enough to have come
up with an insightful meaning to the 1/2 k x^2 - please post it if
you have.