I regard this as an analog of a totally inelastic collision, where a common
final velocity between two interacting particles mandates a definite
dissipation of kinetic energy. This is a "collision" between the rotational
and translational modes of the disk, mediated by the floor/friction
mechanism. If you require a common final "velocity" in the sense that V=R*W
as the end state, dissipation is mandated.
Consider a spinning toothed wheel suddenly engaging a fixed toothed rack -
the inelastic collision becomes evident.
----- Original Message -----
From: "Brian Whatcott" <betwys@DIRECTVINTERNET.COM>
To: <PHYS-L@lists.nau.edu>
Sent: Tuesday, October 29, 2002 7:25 PM
Subject: Re: When Physical Intuition Fails
| . . .
| Or am I missing some feature of the math model that must exclude
| the high mu, no slip case from realisation?
|
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