Chronology Current Month Current Thread Current Date
[Year List] [Month List (current year)] [Date Index] [Thread Index] [Thread Prev] [Thread Next] [Date Prev] [Date Next]

Re: plug and chug



1. The same skier comes off the hill and stops on a level spot. Her
friend pushes the skier forward with a force of 15.0 N. Find the
skier's acceleration. (The coefficient of friction was given as
.0500, the skier's mass as 75.0 kg).

<NITPICK> I think we may have discussed this one before. My best
answer would be that the problem is ill-posed. Assuming that the
skier is initially at rest (which the problem seems to be clear
about), then her friend may "push on the skier's back" with a force
of 15 N but her friend can't "push the skier forward" with a force
that small.</NITPICK>

Of course, it does depend on how you interpret the words but I think
most people would interpret the words as implying that the skier
*does* move forward. I don't mind "tricky" questions in general, but
trickiness shouldn't depend upon the purposeful choice of misleading
words and I suspect that the class results could be significantly
different if the words "the skier forward" were replaced with "on the
skier's back."

--
John Mallinckrodt mailto:ajm@csupomona.edu
Cal Poly Pomona http://www.csupomona.edu/~ajm

Visit my Interactive Physics[TM] page at
http://www.csupomona.edu/~ajm/ip.html
(featuring new "Molecular Interaction" modules)

... and get FREE MUSIC (worth every penny) at
http://www.csupomona.edu/~ajm/personal.html#music