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Re: Unconventional Dynamo (TPT, April, 2002)



1) There is a motional emf arising from the qVxB "generator effect"
2) Since the conductor is not moving there is no motional (qVxB) effect.
Given the cylindrical symmetry of this magnet's B field, there is no dB/dt
(partial derivative) and so there is no "transformer effect". No emf.
3) The conductor is moving; there is a qVxB motional, "generator effect"
emf. Given the magnetic field's symmetry, it matters not whether the magnet
rotates or not. (The intuitive temptation to expect an emf only and whenever
there is any relative motion between the conductor and the magnet is simply
in error.)

I have submitted a reply to this article to TPT, going into more detail.

Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor
----- Original Message -----
From: "Chuck Britton" <britton@NCSSM.EDU>
. . .Three situations are enumerated:

1) The loop moves around the stationary magnet.

2) The magnet rotates while the loop is stationary. and

3) Both the magnet AND the loop rotate together
with no change in position relative to the other.

In which cases (if any!) will the galvanometer indicate that emf
and/or current is being generated. . . .



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